Chapter 6 Programming Exercise [ANSI C] Part-1

Problem 6.1:  Given a number, write a program using while loop to reverse the digits of the number.For example ,the number 

12345

should be written as 

54321.

Solution: #include <stdio.h>

int main()

{

    int n;

    printf(“enter your number to revice\n”);

    scanf(“%d”,&n);

    printf(“reverse of your number %d is : “,n);

    while(n!=0)

        {

        printf(“%d”,n%10);

        n=n/10;

        }

    printf(“\n”);

}

Problem 6.2: The factorial of an integer m is the product of consecutive integers from 1 to m. That is, factorial m=m!=m x (m-1) x …….. x 1.

Write a program that computes and prints a lable of factorials for any given m.

Solution: #include <stdio.h>

int main()

{

    int m,i,f=1;

    printf(“enter the number=\n”);

    scanf(“%d”,&m);

    for(i=m; i>=1; i–)

    {

        f=f*i;

    }

    printf(“Factorial=%d\n”,f);

}

Problem 6.3: Write a program to compute the sum of the digits of a given integer number.

Solution: #include<stdio.h>

void main()

{

    int n,digit,sum=0,temp;

    printf(“enter your number \n”);

    scanf(“%d”,&n);

    temp=n;

    while(n!=0)

        {

        digit=n%10;

        sum=sum+digit;

        n=n/10;

        }

     printf(“sum of all digit %d is: %d\n”,temp,sum);

}

Problem 6.4: The numbers in the sequence

1 1 2 3 5 8 13 21 ………………

Solution: #include <stdio.h>

int main()

{

    int i, n, a = 0, b = 1, c,sum=0;

    printf(“Enter the number: “);

    scanf(“%d”, &n);

    printf(“Fibonacci Series is till %d: “,n);

    for (i = 1; i <= n; i++)

    {

        sum=sum+a;

        printf(“%d “,a );

        c = a + b;

        a = b;

        b = c;

    }

    printf(“\nsum of this series is :%d\n”,sum);

    return 0;

}

Problem 6.5: Rewrite a program of the example 6.1 using the for statement.

Solution: #include <stdio.h>

int main()

{

     int i,n;

    printf(“enter your number to reverce\n”);

    scanf(“%d”,&n);

    printf(“reverce of %d is :”,n);

    for(i=0;n!=0;i++)

        {

        printf(“%d”,n%10);

        n=n/10;

        }

    return 0;

}

Problem 6.7: write a program to print the following outputs using for loop

1

2 2

3 3 3

4 4 4 4

5 5 5 5 5

Solution: #include <stdio.h>

int main()

{

     int i,j,n;

    printf(“enter your num=\n”);

    scanf(“%d”,&n);

    for(i=1; i<=n; i++)

        {

           for (j=1; j<=i; j++)

           printf(“%d “,i);

           printf(“\n”);

        }

    return 0;

}